7.2. Integration Techniques
Example 7.2.4(b): Applying the Substitution Rule
To find
u = cx + d so thatTherefore
du/dx = c, or du = c dx
To findf(cx + d) dx =
f(u) dx =
=1/c f(u) c dx = 1/c
f(u) du =
= 1/c [F(u(b)) - F(u(a))] = 1/c [F(cb + d) - F(ca + d)]

u = cx2 so thatTherefore
du/dx = 2cx or du = 2cx dx
To findx f(cx2) dx =
x f(u) dx =
=1/2c f(u) 2cx dx =
1/2c f(u) du =
= 1/2c [ F(u(b)) - F(u(a)) ] = = 1/2c [ F(cb2) - F(ca2) ]

u = f(x) so thatTherefore
du/dx = f'(x), or du = f'(x) dx
f'(x) / f(x) dx =
1/ f(x) f'(x) dx =
1/u du =
= ln(|f(b)|) - ln(|f(a)|)