7.4. Lebesgue Integral
Example 7.4.9(b): Riemann implies Lebesgue Integrable
Show that the converse of the above theorem is false, i.e. not every bounded Lebesgue integrable function is Riemann integrable.The Dirichlet function restricted to [0, 1] is bounded and Lebesgue integrable (with the intgral zero), while it is not Riemann integrable.